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## From a Solid Cylinder Whose Height is 2.4 cm and Diameter is 1.4 cm Conical Cavity Find The Volume

Let us now know the correct answer to *From a Solid Cylinder Whose Height is 2.4 and Diameter is 1.4 cm* and not only will we know but also learn how to solve this type of question.

“From a Solid Cylinder Whose Height is 2.4 cm and Diameter is 1.4 cm” – Understanding the Shape and its Characteristics

A cylinder is a three-dimensional geometric shape with two parallel bases that are circular in shape and a solid cylinder is a cylinder with a uniform cross-section throughout its length. In this article, we will be discussing a solid cylinder with a height of 2.4 cm and a diameter of 1.4 cm.

**Solutions:** The conical cavity, with its uniform height and width, has been carved out, resulting in one of the cylinder’s bases not being accounted for in the total surface area of the solid.

Let us find the area of the remaining solid by using this formula;

CSA of the cylinder = 2πrh

Area of the base of the cylinder = πr^{2}, where r and h are radius and height of the cylinder respectively.

CSA of the cone = πrl

Slant height of the cone, l = √[r^{2} + h^{2}]

Where r represents the radius, h stands for the height, and l signifies the slant height of the cone.

Height of cylinder, h = Height of cone = h = 2.4 cm

Diameter of cylinder = diameter of cone = d = 1.4 cm

Radius of cylinder = radius of cone = r = d / 2 = 1.4 / 2 cm = 0.7 cm

Slant height of cone, l = √[r^{2} + h^{2}]

l = √[(0.7 cm)^{2} + (2.4 cm)^{2}]

= √[0.49 cm^{2} + 5.76 cm^{2}]

= √[6.25 cm^{2}]

= 2.5 cm

TSA of the remaining Solid = CSA (cylindrical part) + CSA (conical part) + Area (one cylindrical base)

TSA of the remaining Solid = 2πrh + πrl + πr^{2}

2π are common, Then,

TSA of the remaining Solid = πr (2h + l + r)

= 22/7 × 0.7 cm × (2 × 2.4 cm + 2.5 cm + 0.7 cm)

= 3.14 × 0.7 cm × (4.8 cm + 3.2 cm)

= 2.198cm × (8cm)

= 2.2 cm × 8 cm

TSA of the remaining Solid = 17.6 cm^{2}

TSA of the remaining Solid = 18 cm^{2 }(Near About)

Hope you have got the answer to your question *From a Solid Cylinder Whose Height is 2.4 cm and Diameter is 1.4 cm Conical Cavity Find The Volume*, now let us know some more questions related to it.

**Hence, the total surface area of the remaining solid to the near about cm ^{2} is approximately 18 cm^{2}.**

From a solid cylinder whose height is 2.4 cm and diameter is 1.4 cm, it can be determined that the cylinder’s height has remained constant since the moment it was created. The diameter, on the other hand, has been gradually decreasing over time due to wear and tear. As time progressed, the cylinder’s height remained unchanged while its diameter diminished continuously. Nevertheless, the cylinder’s height of 2.4 cm still remained the same even after a prolonged period of time. With the passage of time, it’s possible that the diameter may continue to decrease, but the cylinder’s height will remain steadfast at 2.4 cm.

First and foremost, it is important to understand that the diameter of a cylinder is the distance across its widest point, which in this case is 1.4 cm. The height of a cylinder, on the other hand, is the distance from the top to the bottom of the cylinder. In this case, the height of the cylinder is 2.4 cm.

The volume of this solid cylinder can be calculated using the formula πr^{2}h, where r is the radius of the cylinder and h is the height. By substituting the values, we get the volume of this cylinder to be approximately 4.06 cm^{3}.

The surface area of this solid cylinder can be calculated using the formula 2πr(h + r), where r is the radius of the cylinder and h is the height. By substituting the values, we get the surface area of this cylinder to be approximately 13.44 cm^{2}.

In conclusion, a solid cylinder with a height of 2.4 cm and a diameter of 1.4 cm is a three-dimensional geometric shape with two parallel circular bases. Its volume is approximately 4.06 cm^{3}, and its surface area is approximately 13.44 cm^{2}. Understanding the characteristics of this solid cylinder is important for various applications in fields such as mathematics, engineering, and physics.

**From a Solid Cylinder Whose Height is 8cm and Radius 6 cm, a Conical Cavity of height 8 cm and of base radius 6 cm is hollowed out, So Find the volume of the remaining solid. And Also, find the total surface area of the remaining solid Cylinder**

Let us now know the correct answer to your new question **From a Solid Cylinder Whose Height is 8cm and Radius 6 cm** and will understand very closely.

**Solutions: **First of all, we will write the thing which is given in the question like its height and radius, etc.

Height of the solid cylinder = h = 8 cm

Radius of the solid cylinder = r = 6 cm

Volume of the solid cylinder = πr^{2}h

= π × 6 × 6 × 8 cm^{3}

= 3.14 × 6 × 6 × 8 cm^{3}

= 3.14 × 288 cm^{3}

= 904.32 cm^{3}

The curved Surface area of the solid cylinder = 2πrh

Height of the conical cavity = h = 8 cm

Radius of the conical cavity = r = 6 cm

Volume of the conical cavity = 1/3 πr^{2}h

= 1/3 × π× 6 × 6 × 8 cm^{3}

= 1/3 × 3.14 × 6 × 6 × 8 cm^{3}

= 1/3 × 3.14 ×288 cm^{3}

= 1/3 × 904.32 cm^{3}

= 301.44 cm^{3}

Let l be the slant height of the conical cavity

l^{2} = r^{2} + h^{2}

Put all the value

l^{2} = (6^{2} + 8^{2}) cm^{2}

l^{2} = (36 + 64) cm^{2}

l^{2} = 100 cm^{2}

l = √(100) cm^{2}

l = 10 cm

Curved Surface area of the conical cavity = πrl

This problem can also be solved by determining the difference between the volume and total surface area of the original solid cylinder and the conical cavity that has been hollowed out. By subtracting these values, we obtain the volume and total surface area of the remaining solid.

Volume of the remaining solid = 904.32 cm^{3} – 301.44 cm^{3}

= 602.88 cm^{3}

Total surface area of remaining solid = Curved Surface area of the solid cylinder + Curved Surface area of the conical cavity + Area of circular base

Total surface area of the remaining solid = 2πrh + πrl + πr^{2}

Taken πr common

= πr × (2h + l + r)

Put all the value

= 3.14 × 6 × (2 × 8 + 10 + 6) cm^{2}

= 3.14 × 6 × 32 cm^{2}

= 602.88 cm^{2}

Now you must have got the answer of *From a Solid Cylinder Whose Height is 8cm and Radius 6 cm* very well, if you have any other question, then do tell us through the comment. I’ll try to solve that for you too.

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**From a Solid Cylinder Whose Height is 15 cm and Diameter 16 cm, a conical cavity of same height and same diameter is hollowed out, So Find the total surface area**

**Solutions:** Now we will know what is the answer of From a Solid Cylinder Whose Height is 15 cm and Diameter 16 cm and we will know it very easily, so let’s start solving it too.

Height of solid cylinder = h = 15 cm

Radius of the solid cylinder = r = 8 cm

$l²=r2+h2$

**From a Solid Cylinder Whose Height is 2.4 cm**, I have solved more questions related to this so that you can understand better. How did all of you like our information on From a Solid Cylinder Whose Height is 2.4 cm, please tell us through the medium of comments below?

**FAQs Related From a solid cylinder whose height is 2.4 find the volume**

### From a solid cylinder whose height is 2.4 find the volume

The volume of a cylinder can be calculated by using the formula:

V = π * r^2 * h

Where r is the radius of the base of the cylinder and h is its height. In this case, the height of the cylinder is given as 2.4. If the radius is not given, you’ll need to determine it first in order to calculate the volume.

### From a solid cylinder whose height is 15 cm and diameter 16 cm

The volume of a cylinder can be calculated by using the formula:

V = π * r^2 * h

Where r is the radius of the base of the cylinder and h is its height. In this case, the height of the cylinder is given as 15 cm and the diameter is 16 cm. To calculate the radius, divide the diameter by 2:

r = d/2 = 16 cm / 2 = 8 cm

So, the volume of the cylinder is:

V = π * r^2 * h = π * (8 cm)^2 * 15 cm = 615.75 cm^3

### From a solid cylinder whose height is 8cm and radius 6 cm, a conical cavity

The volume of a cylinder with a conical cavity can be calculated by subtracting the volume of the cone from the volume of the original cylinder. The formula to calculate the volume of a cylinder is:

V = π * r^2 * h

Where r is the radius of the base of the cylinder and h is its height. In this case, the height of the cylinder is given as 8 cm and the radius is 6 cm. So, the volume of the original cylinder is:

V_cylinder = π * r^2 * h = π * (6 cm)^2 * 8 cm = 452.16 cm^3

To calculate the volume of the conical cavity, you’ll need to know the height of the cone (let’s call it h_cone). The formula to calculate the volume of a cone is:

V_cone = (1/3) * π * r^2 * h_cone

Where r is the radius of the base of the cone. The radius of the cone is the same as the radius of the cylinder, which is 6 cm. So, the volume of the cone is:

V_cone = (1/3) * π * (6 cm)^2 * h_cone = (1/3) * π * 6^2 * h_cone

Finally, to calculate the volume of the cylinder with the conical cavity, subtract the volume of the cone from the volume of the original cylinder:

V_cylinder_with_cavity = V_cylinder – V_cone = 452.16 cm^3 – (1/3) * π * 6^2 * h_cone

Note that the value of h_cone is not given in this problem, so the exact volume of the cylinder with the conical cavity cannot be calculated.